it requires 2,500 joules to raise a certain amount of water (c = 4.186 j/g°c) from 20.0°c to 60.0°c. what is…

it requires 2,500 joules to raise a certain amount of water (c = 4.186 j/g°c) from 20.0°c to 60.0°c. what is the mass of the water that is being heated? 15 g 40 g 63 g 80 g

it requires 2,500 joules to raise a certain amount of water (c = 4.186 j/g°c) from 20.0°c to 60.0°c. what is the mass of the water that is being heated? 15 g 40 g 63 g 80 g

Answer

Explanation:

Step1: Calculate temperature change

$\Delta T=T_2 - T_1=60.0^{\circ}C - 20.0^{\circ}C = 40.0^{\circ}C$

Step2: Use heat - mass - specific heat formula

The formula for heat is $Q = mc\Delta T$, where $Q$ is heat, $m$ is mass, $c$ is specific heat capacity, and $\Delta T$ is temperature change. We need to solve for $m$, so $m=\frac{Q}{c\Delta T}$. Substitute $Q = 2500\ J$, $c = 4.186\ J/g^{\circ}C$ and $\Delta T=40.0^{\circ}C$ into the formula: $m=\frac{2500\ J}{4.186\ J/g^{\circ}C\times40.0^{\circ}C}\approx15\ g$

Answer:

15 g