what is the resistance of a light bulb if a potential difference of 120 v will produce a current of 0.5 a in…

what is the resistance of a light bulb if a potential difference of 120 v will produce a current of 0.5 a in the bulb?\n0.0042 ω\n0.5 ω\n60 ω\n240 ω

what is the resistance of a light bulb if a potential difference of 120 v will produce a current of 0.5 a in the bulb?\n0.0042 ω\n0.5 ω\n60 ω\n240 ω

Answer

Answer:

D. 240 Ω

Explanation:

Step1: Use Ohm's Law formula

Ohm's Law is (V = IR), where (V) is voltage, (I) is current, and (R) is resistance. We need to solve for (R), so we can rewrite the formula as (R=\frac{V}{I}).

Step2: Substitute the given values

Given (V = 120\space V) and (I=0.5\space A). Substitute these into the formula: (R=\frac{120}{0.5}).

Step3: Calculate the value of (R)

(R = 240\space\Omega) (since (\frac{120}{0.5}=120\div\frac{1}{2}=120\times2 = 240)).