5. what is the resulting volume of an 6403 ml balloon at celsius boiling point of water that was placed in a…
5. what is the resulting volume of an 6403 ml balloon at celsius boiling point of water that was placed in a container of ice water at 8°c?
Answer
Explanation:
Step1: Identificar las magnitudes iniciales y finales
Temperatura inicial $T_1 = 100^{\circ}C=(100 + 273)K=373K$, volumen inicial $V_1 = 6403mL$, temperatura final $T_2=(8 + 273)K = 281K$.
Step2: Aplicar la ley de Charles
La ley de Charles establece que $\frac{V_1}{T_1}=\frac{V_2}{T_2}$. Re - arreglamos la ecuación para despejar $V_2$: $V_2=\frac{V_1\times T_2}{T_1}$.
Step3: Sustituir valores
$V_2=\frac{6403mL\times281K}{373K}$. $V_2=\frac{1799243}{373}mL\approx4824mL$.
Answer:
$4824mL$