if the rock has a mass of 1098 grams and a volume of 122 cm³, its density is \n\na. 133,956…

if the rock has a mass of 1098 grams and a volume of 122 cm³, its density is \n\na. 133,956 $\frac{g}{cm^{3}}$ \nb. 976 $\frac{g}{cm^{3}}$ \nc. 9 $\frac{g}{cm^{3}}$ \nd. 0.11 $\frac{g}{cm^{3}}$

if the rock has a mass of 1098 grams and a volume of 122 cm³, its density is \n\na. 133,956 $\frac{g}{cm^{3}}$ \nb. 976 $\frac{g}{cm^{3}}$ \nc. 9 $\frac{g}{cm^{3}}$ \nd. 0.11 $\frac{g}{cm^{3}}$

Answer

Explanation:

Step1: Recall density formula

The formula for density $\rho$ is $\rho=\frac{m}{V}$, where $m$ is mass and $V$ is volume.

Step2: Substitute values

Given $m = 1098$ g and $V=122$ cm³, then $\rho=\frac{1098}{122}$.

Step3: Calculate density

$\frac{1098}{122}=9$ g/cm³.

Answer:

C. $9\frac{\text{g}}{\text{cm}^3}$