when a rocket that weighs 2400 n on earth is fired the force of propulsion is 4000 n. find the acceleration…

Explanation:

Step1: Find the mass of the rocket

We know that weight (W = mg). Given (W = 2400\space N) and (g=9.8\space m/s^{2}). Then (m=\frac{W}{g}). (m=\frac{2400}{9.8}\space kg\approx244.9\space kg)

Step2: Apply Newton's second law (F_{net}=ma)

The net force (F_{net}=F - W), where (F = 4000\space N) and (W = 2400\space N). So (F_{net}=4000 - 2400=1600\space N) Since (F_{net}=ma), then (a=\frac{F_{net}}{m}) Substitute (m = \frac{2400}{9.8}\space kg) and (F_{net}=1600\space N) into the formula: (a=\frac{1600}{\frac{2400}{9.8}}) (a=\frac{1600\times9.8}{2400}\space m/s^{2}) (a=\frac{15680}{2400}\space m/s^{2}\approx6.53\space m/s^{2})

Answer:

(6.53\space m/s^{2})