a rod of iron of uniform density has a thickness such that a one - inch - long segment of it weighs 3.88…

a rod of iron of uniform density has a thickness such that a one - inch - long segment of it weighs 3.88 ounces. given that there are 0.035273 ounces in a gram and 2.54 centimeters in an inch, how many grams would a 14.79 cm length of the same iron rod weigh?\na. 73.30 g\nb. 274.49 g\nc. 640.51 g\nd. 1,626.89 g

a rod of iron of uniform density has a thickness such that a one - inch - long segment of it weighs 3.88 ounces. given that there are 0.035273 ounces in a gram and 2.54 centimeters in an inch, how many grams would a 14.79 cm length of the same iron rod weigh?\na. 73.30 g\nb. 274.49 g\nc. 640.51 g\nd. 1,626.89 g

Answer

Explanation:

Step1: Convert length to inches

Since 2.54 cm = 1 inch, for a 14.79 - cm length, the length in inches $l=\frac{14.79}{2.54}$ inches. $l=\frac{14.79}{2.54}=5.823$ inches.

Step2: Find weight in ounces

A 1 - inch segment weighs 3.88 ounces, so for a 5.823 - inch segment, the weight in ounces $W_{oz}=3.88\times5.823$ ounces. $W_{oz}=3.88\times5.823 = 22.69324$ ounces.

Step3: Convert weight to grams

Since 0.035273 ounces = 1 gram, the weight in grams $W_{g}=\frac{22.69324}{0.035273}$ grams. $W_{g}=\frac{22.69324}{0.035273}=640.51$ grams.

Answer:

c. 640.51 g