the rydberg constant is 3.3 x 10^15 hz. this value is also\nthe frequency of light emitted by our sun.\nthe…

the rydberg constant is 3.3 x 10^15 hz. this value is also\nthe frequency of light emitted by our sun.\nthe ionization frequency of iron.\nthe average frequency of electromagnetic radiation.\nthe ionization frequency of hydrogen.\n\nquestion 2\n1 pts\nwhat is the frequency of light released when an electron moves from the 2nd energy level to the 1st energy level in hydrogen (dont reach for a calculator, you should be able to estimate 3/4s of a number like 3.3).\n2.5 x 10^12 hz\n3.3 x 10^18 hz\n3.3 x 10^14 hz\n2.5 x 10^15 hz\n\nquestion 3\n1 pts\nin a hydrogen atom which transition would emit the longest wavelength of light?\nn=2 to n=1\nn=4 to n=1\nn=3 to n=1\nn=6 to n=5

the rydberg constant is 3.3 x 10^15 hz. this value is also\nthe frequency of light emitted by our sun.\nthe ionization frequency of iron.\nthe average frequency of electromagnetic radiation.\nthe ionization frequency of hydrogen.\n\nquestion 2\n1 pts\nwhat is the frequency of light released when an electron moves from the 2nd energy level to the 1st energy level in hydrogen (dont reach for a calculator, you should be able to estimate 3/4s of a number like 3.3).\n2.5 x 10^12 hz\n3.3 x 10^18 hz\n3.3 x 10^14 hz\n2.5 x 10^15 hz\n\nquestion 3\n1 pts\nin a hydrogen atom which transition would emit the longest wavelength of light?\nn=2 to n=1\nn=4 to n=1\nn=3 to n=1\nn=6 to n=5

Answer

Explanation:

Step1: Recall Rydberg constant property

The Rydberg constant is related to the ionization frequency of hydrogen.

Step2: Analyze Question 2

Estimate 3/4 of 3.3. 3.3×3/4 = 2.475≈2.5, and for hydrogen electron transition from n = 2 to n = 1, the frequency is on the order of 10^15 Hz.

Step3: Analyze Question 3

Use the formula E=h*c/λ. Smaller energy difference gives longer - wavelength. The transition from n = 6 to n = 5 has the smallest energy difference among the given options.

Answer:

Question 1: the ionization frequency of hydrogen Question 2: 2.5 x 10^15 Hz Question 3: n=6 to n=5