sample a\nmass of each particle: 46 u\naverage particle speed: 1,500 m/s\nwhich sample has the higher…

Explanation:

Step1: Recall temperature - speed relation

The temperature of a gas is related to the average kinetic energy of its particles. The average kinetic energy formula is $K_{avg}=\frac{3}{2}kT$, and also $K_{avg}=\frac{1}{2}mv^{2}$. Since the average particle speed ($v = 1500$ m/s) is the same for both samples, and temperature is a measure of the average kinetic - energy of particles, and kinetic energy depends on speed and mass ($K=\frac{1}{2}mv^{2}$), but when speed is the same, the average kinetic energy per particle is the same for both samples. So the temperature is the same.

Step2: Recall pressure - speed and mass relation

The pressure of a gas is related to the momentum transfer of particles with the walls of the container. The momentum of a particle is $p = mv$. For a given volume and number of particles, more massive particles (with the same speed) will transfer more momentum per collision with the walls. Sample A has particles with a mass of 46 u and sample B has particles with a mass of 44 u. Since the speed is the same, particles in sample A will transfer more momentum per collision, resulting in higher pressure.

Answer:

1. neither; the samples have the same temperature
2. sample A