a sample of an unknown substance has a mass of 0.158 kg. if 2,510.0 j of heat is required to heat the…

a sample of an unknown substance has a mass of 0.158 kg. if 2,510.0 j of heat is required to heat the substance from 32.0°c to 61.0°c, what is the specific heat of the substance? use q = mc_pδt. 0.171 j/(g°c) 0.548 j/(g°c) 15.9 j/(g°c) 86.6 j/(g°c)

a sample of an unknown substance has a mass of 0.158 kg. if 2,510.0 j of heat is required to heat the substance from 32.0°c to 61.0°c, what is the specific heat of the substance? use q = mc_pδt. 0.171 j/(g°c) 0.548 j/(g°c) 15.9 j/(g°c) 86.6 j/(g°c)

Answer

Explanation:

Step1: Convert mass to grams

$m = 0.158\ kg=0.158\times1000\ g = 158\ g$

Step2: Calculate temperature change

$\Delta T=T_2 - T_1=61.0^{\circ}C - 32.0^{\circ}C=29.0^{\circ}C$

Step3: Rearrange the heat - formula for specific heat

$q = mC_p\Delta T$, so $C_p=\frac{q}{m\Delta T}$

Step4: Substitute values

$C_p=\frac{2510.0\ J}{158\ g\times29.0^{\circ}C}=\frac{2510.0}{4582}\ J/(g^{\circ}C)\approx0.548\ J/(g^{\circ}C)$

Answer:

$0.548\ J/(g^{\circ}C)$