in 8 seconds, a car goes from traveling at 29 m/s to 21 m/s. what is the acceleration of the car? a = ? m/s²…

in 8 seconds, a car goes from traveling at 29 m/s to 21 m/s. what is the acceleration of the car? a = ? m/s² enter the sign (+ or -) and the magnitude. remember: a = δv/t

in 8 seconds, a car goes from traveling at 29 m/s to 21 m/s. what is the acceleration of the car? a = ? m/s² enter the sign (+ or -) and the magnitude. remember: a = δv/t

Answer

Explanation:

Step1: Identify initial and final velocities and time

Initial velocity $v_0 = 29\ m/s$, final velocity $v = 21\ m/s$, time $t=8\ s$.

Step2: Calculate the change in velocity

$\Delta v=v - v_0=21 - 29=- 8\ m/s$.

Step3: Calculate acceleration

Using the formula $a=\frac{\Delta v}{t}$, substitute $\Delta v=-8\ m/s$ and $t = 8\ s$. So $a=\frac{-8}{8}=-1\ m/s^{2}$.

Answer:

$-1$