in 8 seconds, a car goes from traveling at 29 m/s to 21 m/s. what is the acceleration of the car? a =…

in 8 seconds, a car goes from traveling at 29 m/s to 21 m/s. what is the acceleration of the car? a = ? $\frac{m}{s^{2}}$ enter the sign (+ or -) and the magnitude. remember: a = $\frac{delta v}{t}$

in 8 seconds, a car goes from traveling at 29 m/s to 21 m/s. what is the acceleration of the car? a = ? $\frac{m}{s^{2}}$ enter the sign (+ or -) and the magnitude. remember: a = $\frac{delta v}{t}$

Answer

Explanation:

Step1: Calculate the change in velocity

$\Delta v=v_f - v_i=21 - 29=- 8$ m/s

Step2: Use the acceleration formula

$a=\frac{\Delta v}{t}=\frac{-8}{8}=-1$ m/s²

Answer:

-1 m/s²