section 6.1\n1. while an object is moving at a constant 20 m/s, a 5 n force pushes the object to the left…

section 6.1\n1. while an object is moving at a constant 20 m/s, a 5 n force pushes the object to the left. at the same time, a 5 n force is pushing the object to the right. what will the objects velocity be after 10 seconds?

section 6.1\n1. while an object is moving at a constant 20 m/s, a 5 n force pushes the object to the left. at the same time, a 5 n force is pushing the object to the right. what will the objects velocity be after 10 seconds?

Answer

Explanation:

Step1: Analyze the net force

The two forces are (5N) to the left and (5N) to the right. Using the formula for net force (F_{net}=F_1 + F_2) (where (F_1=- 5N) (left - direction taken as negative) and (F_2 = 5N) (right - direction taken as positive)). So, (F_{net}=-5 + 5=0N).

Step2: Apply Newton's first law

According to Newton's first law of motion, if (F_{net} = 0), then the acceleration (a=\frac{F_{net}}{m}=0) (where (m) is the mass of the object). The kinematic equation is (v = v_0+at). Since (a = 0), (v=v_0).

Answer:

The object's velocity after (10) seconds is (20m/s)