select the appropriate equation to convert from kelvin to degrees fahrenheit.\n$t_f = \\left(\\frac{5^{circ}f…

select the appropriate equation to convert from kelvin to degrees fahrenheit.\n$t_f = \\left(\\frac{5^{circ}f}{9^{circ}c}\\right)\\left\\left(t_k - 273k\\right)\\left(\\frac{1^{circ}c}{1k}\\right)\\right+32^{circ}f$\n$t_f = \\left(\\frac{9^{circ}f}{5^{circ}c}\\right)\\left\\left(t_k + 273k\\right)\\left(\\frac{1^{circ}c}{1k}\\right)\\right+32^{circ}f$\n$t_f = \\left(\\frac{9^{circ}f}{5^{circ}c}\\right)\\left\\left(t_k - 273k\\right)\\left(\\frac{1^{circ}c}{1k}\\right)\\right+32^{circ}f$\n$t_f = \\left(\\frac{9^{circ}f}{5^{circ}c}\\right)\\left\\left(t_k - 273k\\right)\\left(\\frac{1^{circ}c}{1k}\\right)\\right-32^{circ}f$

select the appropriate equation to convert from kelvin to degrees fahrenheit.\n$t_f = \\left(\\frac{5^{circ}f}{9^{circ}c}\\right)\\left\\left(t_k - 273k\\right)\\left(\\frac{1^{circ}c}{1k}\\right)\\right+32^{circ}f$\n$t_f = \\left(\\frac{9^{circ}f}{5^{circ}c}\\right)\\left\\left(t_k + 273k\\right)\\left(\\frac{1^{circ}c}{1k}\\right)\\right+32^{circ}f$\n$t_f = \\left(\\frac{9^{circ}f}{5^{circ}c}\\right)\\left\\left(t_k - 273k\\right)\\left(\\frac{1^{circ}c}{1k}\\right)\\right+32^{circ}f$\n$t_f = \\left(\\frac{9^{circ}f}{5^{circ}c}\\right)\\left\\left(t_k - 273k\\right)\\left(\\frac{1^{circ}c}{1k}\\right)\\right-32^{circ}f$

Answer

Explanation:

Step1: Recall temperature - conversion relationships

The relationship between Celsius ($T_C$) and Kelvin ($T_K$) is $T_C=T_K - 273$ (since the zero - point of Celsius is 273 K). The relationship between Celsius and Fahrenheit ($T_F$) is $T_F=\frac{9}{5}T_C + 32$.

Step2: Substitute $T_C$ in terms of $T_K$ into the Fahrenheit - Celsius formula

Substitute $T_C=T_K - 273$ into $T_F=\frac{9}{5}T_C + 32$. We get $T_F=\left(\frac{9^{\circ}F}{5^{\circ}C}\right)\left[\left(T_K - 273K\right)\left(\frac{1^{\circ}C}{1K}\right)\right]+32^{\circ}F$.

Answer:

$T_F=\left(\frac{9^{\circ}F}{5^{\circ}C}\right)\left[\left(T_K - 273K\right)\left(\frac{1^{\circ}C}{1K}\right)\right]+32^{\circ}F$ (the third option from the top in the given list)