select the correct answer.\nan adult human lung has a volume of 2.9 liters. if its volume decreases to 1.2…

select the correct answer.\nan adult human lung has a volume of 2.9 liters. if its volume decreases to 1.2 liters and it contains 0.049 mole of air after it exhales, how many moles of air does it contain when full?\na. 0.025 mol\nb. 0.041 mol\nc. 0.083 mol\nd. 0.12 mol\ne. 0.14 mol

select the correct answer.\nan adult human lung has a volume of 2.9 liters. if its volume decreases to 1.2 liters and it contains 0.049 mole of air after it exhales, how many moles of air does it contain when full?\na. 0.025 mol\nb. 0.041 mol\nc. 0.083 mol\nd. 0.12 mol\ne. 0.14 mol

Answer

Explanation:

Step1: Assume ideal - gas law

At constant temperature and pressure, the number of moles of a gas is proportional to its volume ($n_1/V_1=n_2/V_2$). Let $n_1$ be the number of moles when full, $V_1 = 2.9$ L, $n_2=0.049$ mol, and $V_2 = 1.2$ L.

Step2: Rearrange the formula to solve for $n_1$

$n_1=\frac{n_2V_1}{V_2}$. Substitute the values: $n_1=\frac{0.049\times2.9}{1.2}$. $n_1=\frac{0.1421}{1.2}\approx0.12$ mol.

Answer:

D. 0.12 mol