select the correct answer.\na blacksmith making a tool heats 525 grams of steel to 1230°c. after hammering…

select the correct answer.\na blacksmith making a tool heats 525 grams of steel to 1230°c. after hammering the steel, she places it into a bucket of water to cool it. when she removes the steel from the water, its at 50°c. how much heat does the steel release if its specific heat capacity is 0.486 joules/gram degree celsius?\na. 301,000 joules\nb. 12,800 joules\nc. 1,270 joules\nd. 241 joules\ne. 4.62 joules

select the correct answer.\na blacksmith making a tool heats 525 grams of steel to 1230°c. after hammering the steel, she places it into a bucket of water to cool it. when she removes the steel from the water, its at 50°c. how much heat does the steel release if its specific heat capacity is 0.486 joules/gram degree celsius?\na. 301,000 joules\nb. 12,800 joules\nc. 1,270 joules\nd. 241 joules\ne. 4.62 joules

Answer

Explanation:

Step1: Identify the formula

The formula for heat transfer is $Q = mc\Delta T$, where $Q$ is the heat transferred, $m$ is the mass, $c$ is the specific - heat capacity, and $\Delta T$ is the change in temperature.

Step2: Calculate the change in temperature

$\Delta T=T_{initial}-T_{final}=1230 - 50=1180^{\circ}C$.

Step3: Substitute the values into the formula

Given $m = 525$ g, $c = 0.486$ J/g°C, and $\Delta T=1180^{\circ}C$. Then $Q=mc\Delta T=525\times0.486\times1180$. $Q = 525\times0.486\times1180=525\times573.48 = 301077\approx301000$ J.

Answer:

A. 301,000 joules