select the correct answer. which diagram represents an object in equilibrium? a. applied force = 20 n force…

select the correct answer. which diagram represents an object in equilibrium? a. applied force = 20 n force due to friction = 15 n b. applied force = 20 n force due to friction = 20 n c. applied force = 15 n force due to friction = 25 n d. applied force = 30 n force due to friction = 20 n e. applied force = 30 n force due to friction = 15 n

select the correct answer. which diagram represents an object in equilibrium? a. applied force = 20 n force due to friction = 15 n b. applied force = 20 n force due to friction = 20 n c. applied force = 15 n force due to friction = 25 n d. applied force = 30 n force due to friction = 20 n e. applied force = 30 n force due to friction = 15 n

Answer

Explanation:

Step1: Recall equilibrium condition

An object is in equilibrium when the net - force acting on it is zero. In the case of an object with an applied force and a frictional force acting in opposite directions, the net force $F_{net}=F_{applied}-F_{friction}$. For equilibrium, $F_{net} = 0$, so $F_{applied}=F_{friction}$.

Step2: Analyze each option

  • Option A: $F_{applied}=20\ N$ and $F_{friction}=15\ N$, $F_{net}=20 - 15=5\ N\neq0$.
  • Option B: $F_{applied}=20\ N$ and $F_{friction}=20\ N$, $F_{net}=20 - 20 = 0$.
  • Option C: $F_{applied}=15\ N$ and $F_{friction}=25\ N$, $F_{net}=15 - 25=- 10\ N\neq0$.
  • Option D: $F_{applied}=30\ N$ and $F_{friction}=20\ N$, $F_{net}=30 - 20 = 10\ N\neq0$.
  • Option E: $F_{applied}=30\ N$ and $F_{friction}=15\ N$, $F_{net}=30 - 15 = 15\ N\neq0$.

Answer:

B. applied force = 20 N, force due to friction = 20 N