select the correct answer. ellie is pushing a box of mass 7.0 kilograms with the force of 25 newtons. if the…

select the correct answer. ellie is pushing a box of mass 7.0 kilograms with the force of 25 newtons. if the force of friction is 2.6 newtons, what is the value of acceleration of the box?\na. 0.7 meters/second squared\nb. 2.6 meters/second squared\nc. 3.2 meters/second squared\nd. 3.6 meters/second squared

select the correct answer. ellie is pushing a box of mass 7.0 kilograms with the force of 25 newtons. if the force of friction is 2.6 newtons, what is the value of acceleration of the box?\na. 0.7 meters/second squared\nb. 2.6 meters/second squared\nc. 3.2 meters/second squared\nd. 3.6 meters/second squared

Answer

Explanation:

Step1: Calculate net force

The net force $F_{net}$ is the applied force minus the frictional force. Given $F_{applied}=25$ N and $F_{friction} = 2.6$ N. So, $F_{net}=F_{applied}-F_{friction}=25 - 2.6=22.4$ N.

Step2: Use Newton's second - law

Newton's second - law is $F = ma$, where $F$ is the net force, $m$ is the mass and $a$ is the acceleration. We know $m = 7.0$ kg and $F = 22.4$ N. Rearranging for $a$, we get $a=\frac{F}{m}$. Substituting the values, $a=\frac{22.4}{7.0}=3.2$ m/s².

Answer:

C. 3.2 meters/second squared