select the correct answer.\nwhat is the equivalent resistance in a parallel circuit that has the following…

Explanation:

Step1: Recall parallel - resistance formula

The formula for the equivalent resistance $R_{eq}$ of resistors in parallel is $\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}$, where $R_1 = 6.8\Omega$, $R_2=9.0\Omega$, and $R_3 = 15.0\Omega$.

Step2: Calculate the sum of the reciprocals

$\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}=\frac{1}{6.8}+\frac{1}{9.0}+\frac{1}{15.0}$. $\frac{1}{6.8}\approx0.147$, $\frac{1}{9.0}\approx0.111$, $\frac{1}{15.0}= 0.067$. $\frac{1}{6.8}+\frac{1}{9.0}+\frac{1}{15.0}\approx0.147 + 0.111+0.067=0.325$.

Step3: Find the equivalent resistance

Since $\frac{1}{R_{eq}}\approx0.325$, then $R_{eq}=\frac{1}{0.325}\approx3.08\Omega$.

Answer:

C. 3.08 ohms