select the correct answer.\na force of 19 newtons is applied on a cart of 2 kilograms, and it experiences a…
select the correct answer.\na force of 19 newtons is applied on a cart of 2 kilograms, and it experiences a frictional force of 1.7 newtons. what is the acceleration of the cart?\na. 8.6 meters/second²\nb. 9.0 meters/second²\nc. 9.5 meters/second²\nd. 10.5 meters/second²\ne. 0.8 meters/second²
Answer
Explanation:
Step1: Calculate net force
The net - force $F_{net}$ is the applied force minus the frictional force. Given $F_{applied}=19N$ and $F_{friction}=1.7N$, so $F_{net}=F_{applied}-F_{friction}=19 - 1.7=17.3N$.
Step2: Use Newton's second law
Newton's second law is $F = ma$, where $F$ is the net - force, $m$ is the mass, and $a$ is the acceleration. We know $F_{net}=17.3N$ and $m = 2kg$. Rearranging the formula for acceleration gives $a=\frac{F_{net}}{m}$. Substituting the values, we get $a=\frac{17.3}{2}=8.65m/s^{2}\approx8.6m/s^{2}$.
Answer:
A. 8.6 meters/second²