select the correct answer. for a given launch velocity, at which launch angle does the projectile undergo…

select the correct answer. for a given launch velocity, at which launch angle does the projectile undergo the maximum horizontal displacement? a. 35° b. 45° c. 75° d. 80° e. 90°

select the correct answer. for a given launch velocity, at which launch angle does the projectile undergo the maximum horizontal displacement? a. 35° b. 45° c. 75° d. 80° e. 90°

Answer

Explanation:

Step1: Recall range formula

The horizontal - range formula for a projectile launched with initial velocity (v_0) at an angle (\theta) is (R=\frac{v_0^{2}\sin2\theta}{g}), where (g) is the acceleration due to gravity.

Step2: Find maximum of range function

We know that the function (y = \sin x) has a maximum value of 1. For (y=\sin2\theta), we set (\sin2\theta = 1). Then (2\theta=90^{\circ}), so (\theta = 45^{\circ}).

Answer:

B. (45^{\circ})