select the correct answer.\nobject a attracts object b with a gravitational force of 5 newtons from a given…

select the correct answer.\nobject a attracts object b with a gravitational force of 5 newtons from a given distance. if the distance between the two objects is reduced in half, what will be the changed force of attraction between them?\na. 2.5 newtons\nb. 10 newtons\nc. 15 newtons\nd. 20 newtons\ne. 25 newtons
Answer
Explanation:
Step1: Recall gravitational - force formula
The gravitational force between two objects is given by $F = G\frac{m_1m_2}{r^2}$, where $G$ is the gravitational constant, $m_1$ and $m_2$ are the masses of the two objects, and $r$ is the distance between them. Let the initial force be $F_1 = G\frac{m_1m_2}{r_1^2}=5$ N.
Step2: Analyze the new - distance situation
The new distance $r_2=\frac{r_1}{2}$. The new force $F_2 = G\frac{m_1m_2}{r_2^2}=G\frac{m_1m_2}{(\frac{r_1}{2})^2}=G\frac{m_1m_2}{\frac{r_1^2}{4}} = 4\times G\frac{m_1m_2}{r_1^2}$.
Step3: Calculate the new force
Since $F_1 = G\frac{m_1m_2}{r_1^2}=5$ N, then $F_2 = 4F_1$. Substituting $F_1 = 5$ N, we get $F_2=4\times5 = 20$ N.
Answer:
D. 20 newtons