select the correct answer. which parameter of a projectile depends on the horizontal as well as the vertical…

Explanation:

Step1: Analyze hang - time

Hang - time depends only on the vertical component of the initial velocity. The formula for hang - time $t=\frac{2v_{0y}}{g}$, where $v_{0y}$ is the initial vertical velocity and $g$ is the acceleration due to gravity.

Step2: Analyze range

The range of a projectile $R = v_{0x}t$, where $v_{0x}$ is the initial horizontal velocity and $t=\frac{2v_{0y}}{g}$. So $R=\frac{2v_{0x}v_{0y}}{g}$, which depends on both the horizontal ($v_{0x}$) and vertical ($v_{0y}$) components of the initial velocity.

Step3: Analyze height

The maximum height of a projectile $H=\frac{v_{0y}^{2}}{2g}$, which depends only on the vertical component of the initial velocity.

Step4: Analyze angle of launch

The angle of launch $\theta=\tan^{- 1}(\frac{v_{0y}}{v_{0x}})$ is a ratio - based quantity and not a physical parameter of the motion like range, height etc. It is related to the components but not a parameter that has a direct physical meaning in terms of the motion's extent like range.

Answer:

B. range