select the correct answer. if the resistance remains constant and the voltage doubles, what effect will that…

Explanation:

Step1: Recall power - voltage - resistance formula

The power formula is $P=\frac{V^{2}}{R}$, where $P$ is power, $V$ is voltage, and $R$ is resistance.

Step2: Let the initial voltage be $V_1$ and power be $P_1$

So, $P_1 = \frac{V_1^{2}}{R}$.

Step3: The voltage doubles, so new voltage $V_2 = 2V_1$

The new power $P_2=\frac{V_2^{2}}{R}=\frac{(2V_1)^{2}}{R}=\frac{4V_1^{2}}{R}$.

Step4: Find the ratio of new power to old power

$\frac{P_2}{P_1}=\frac{\frac{4V_1^{2}}{R}}{\frac{V_1^{2}}{R}} = 4$.

Answer:

E. The power will increase by a factor of 4.