select the correct answer.\na stone of mass 0.55 kilograms is released and falls to the ground. measurements…
select the correct answer.\na stone of mass 0.55 kilograms is released and falls to the ground. measurements show that the stone has a kinetic energy of 9.8 joules at the point of impact with the ground. what is the stones velocity when it hits the ground?\na. 6.0 meters/second\nb. 7.2 meters/second\nc. 8.1 meters/second\nd. 9.3 meters/second
Answer
Explanation:
Step1: Recall kinetic - energy formula
The formula for kinetic energy is $K = \frac{1}{2}mv^{2}$, where $K$ is kinetic energy, $m$ is mass, and $v$ is velocity. We are given that $K = 9.8\ J$ and $m=0.55\ kg$. We need to solve for $v$. First, rewrite the formula for $v$: $v^{2}=\frac{2K}{m}$
Step2: Substitute the given values
Substitute $K = 9.8\ J$ and $m = 0.55\ kg$ into the formula $v^{2}=\frac{2K}{m}$: $v^{2}=\frac{2\times9.8}{0.55}=\frac{19.6}{0.55}\approx35.64$
Step3: Solve for $v$
Take the square - root of both sides: $v=\sqrt{35.64}\approx6.0\ m/s$
Answer:
A. 6.0 meters/second