select the correct answer.\nthe volume of helium in a blimp is 6.28×10^9 milliliters. the density of helium…

select the correct answer.\nthe volume of helium in a blimp is 6.28×10^9 milliliters. the density of helium in the blimp is 0.1786 $\frac{kilogram}{meter^3}$. find the mass of the helium in the blimp. (hint: 1,000 l = 1 cubic meter.)\na. 1,120 kg\nb. 1.12 kg\nc. 3.52×10^7 kg\nd. 2,840 kg

select the correct answer.\nthe volume of helium in a blimp is 6.28×10^9 milliliters. the density of helium in the blimp is 0.1786 $\frac{kilogram}{meter^3}$. find the mass of the helium in the blimp. (hint: 1,000 l = 1 cubic meter.)\na. 1,120 kg\nb. 1.12 kg\nc. 3.52×10^7 kg\nd. 2,840 kg

Answer

Explanation:

Step1: Convert volume to cubic - meters

We know that $1\ L = 1000\ mL$ and $1000\ L=1\ m^{3}$. So, $1\ m^{3}=10^{6}\ mL$. The volume $V = 6.28\times10^{9}\ mL$. Then $V=\frac{6.28\times 10^{9}}{10^{6}}\ m^{3}=6.28\times10^{3}\ m^{3}$.

Step2: Use the density - mass formula

The density formula is $\rho=\frac{m}{V}$, where $\rho$ is density, $m$ is mass, and $V$ is volume. We are given $\rho = 0.1786\ \frac{kg}{m^{3}}$ and $V = 6.28\times10^{3}\ m^{3}$. Rearranging the formula for mass gives $m=\rho V$. Substitute the values: $m=0.1786\times6.28\times 10^{3}\ kg$. $m=(0.1786\times6.28)\times10^{3}\ kg$. $0.1786\times6.28 = 1.121608$. So, $m = 1.121608\times10^{3}\ kg\approx1120\ kg$.

Answer:

A. 1,120 kg