select the correct answer.\na wire that is 0.86 meters long is moved perpendicularly through a constant…

Explanation:

Step1: Recall the formula for emf

The formula for motional emf is $\epsilon = Blv$, where $B$ is the magnetic - field strength, $l$ is the length of the wire, and $v$ is the velocity of the wire.

Step2: Identify the given values

$B = 0.035\ N/(A\cdot m)$, $l = 0.86\ m$, and $v = 6.0\ m/s$.

Step3: Substitute the values into the formula

$\epsilon=(0.035\ N/(A\cdot m))\times(0.86\ m)\times(6.0\ m/s)$. First, calculate $(0.035)\times(0.86)\times(6.0)=0.035\times5.16 = 0.1806\ V\approx0.18\ V$.

Answer:

D. 0.18 volts