select all the correct answers. two buses leave school moving in opposite directions. after 15 minutes, they…

select all the correct answers. two buses leave school moving in opposite directions. after 15 minutes, they are both 10 miles away from the school. which statements correctly describe the motion of the buses? the velocity of the buses is equal. the average speed of the buses is equal. the average speed of the buses is not equal. the velocity of the buses is not equal. both buses move with constant velocity the entire trip.

select all the correct answers. two buses leave school moving in opposite directions. after 15 minutes, they are both 10 miles away from the school. which statements correctly describe the motion of the buses? the velocity of the buses is equal. the average speed of the buses is equal. the average speed of the buses is not equal. the velocity of the buses is not equal. both buses move with constant velocity the entire trip.

Answer

Explanation:

Step1: Define speed and velocity

Speed is a scalar quantity (magnitude only), velocity is a vector quantity (magnitude and direction).

Step2: Analyze speed

Both buses travel 10 miles in 15 minutes. Average - speed formula is $v_{avg}=\frac{d}{t}$. Since $d = 10$ miles and $t=15$ minutes for both, their average - speeds are equal.

Step3: Analyze velocity

They move in opposite directions. Velocity has a direction component. So, their velocities are not equal as directions are different.

Step4: Analyze constant velocity

We have no information about whether their speed and direction remain constant throughout the 15 - minute trip. So, we cannot say they move with constant velocity.

Answer:

The average speed of the buses is equal. The velocity of the buses is not equal.