select all the correct answers. two buses leave school moving in opposite directions. after 15 minutes, they…

select all the correct answers. two buses leave school moving in opposite directions. after 15 minutes, they are both 10 miles away from the school. which statements correctly describe the motion of the buses? the velocity of the buses is equal the average speed of the buses is equal the average speed of the buses is not equal the velocity of the buses is not equal both buses move with constant velocity the entire trip

select all the correct answers. two buses leave school moving in opposite directions. after 15 minutes, they are both 10 miles away from the school. which statements correctly describe the motion of the buses? the velocity of the buses is equal the average speed of the buses is equal the average speed of the buses is not equal the velocity of the buses is not equal both buses move with constant velocity the entire trip

Answer

Explanation:

Step1: Define speed and velocity

Speed (scalar: magnitude); velocity (vector: magnitude + direction).

Step2: Calculate average speed

Both buses: distance=10 miles, time=15 min. Average speed = 10/(15/60)=40 mph (same for both).

Step3: Analyze velocity

Opposite directions → velocity vectors differ (direction).

Step4: Evaluate constant velocity

No info on motion during trip; cannot confirm constant velocity.

Answer:

The average speed of the buses is equal, The velocity of the buses is not equal.