select the correct equation to convert from kelvin to degrees celsius.\n$t_c=(t_k + 273k)(\\frac{1k}{1^{circ}…

select the correct equation to convert from kelvin to degrees celsius.\n$t_c=(t_k + 273k)(\\frac{1k}{1^{circ}c})$ \n$t_c=(t_k + 273k)(\\frac{1^{circ}c}{1k})$ \n$t_c=(t_k - 273^{circ}c)(\\frac{1k}{1^{circ}c})$ \n$t_c=(t_k - 273k)(\\frac{1^{circ}c}{1k})$

select the correct equation to convert from kelvin to degrees celsius.\n$t_c=(t_k + 273k)(\\frac{1k}{1^{circ}c})$ \n$t_c=(t_k + 273k)(\\frac{1^{circ}c}{1k})$ \n$t_c=(t_k - 273^{circ}c)(\\frac{1k}{1^{circ}c})$ \n$t_c=(t_k - 273k)(\\frac{1^{circ}c}{1k})$

Answer

Explanation:

Step1: Recall temperature - conversion relation

The relation between Celsius ($T_C$) and Kelvin ($T_K$) is $T_C=T_K - 273.15\approx T_K - 273$. The conversion factor between Celsius and Kelvin is 1 K = 1°C, so when converting from Kelvin to Celsius, we subtract 273 K from the Kelvin temperature and use the conversion factor $\frac{1^{\circ}C}{1K}$.

Step2: Identify the correct equation

The correct equation for converting from Kelvin to Celsius is $T_C=(T_K - 273K)\left(\frac{1^{\circ}C}{1K}\right)$.

Answer:

$T_C=(T_K - 273K)\left(\frac{1^{\circ}C}{1K}\right)$ (the last option)