a series circuit contains three 2 ω resistors and a 6 ω resistor. the current in each resistor is 4.0 a…

Explanation:

Step1: Calculate total resistance

In a series - circuit, the total resistance $R_{total}$ is the sum of individual resistances. There are three $2\Omega$ resistors and one $6\Omega$ resistor. So $R_{total}=3\times2 + 6=6 + 6=12\Omega$.

Step2: Use Ohm's law

Ohm's law is $V = IR$, where $V$ is voltage, $I$ is current, and $R$ is resistance. Given $I = 4.0A$ and $R_{total}=12\Omega$. Then $V=4\times12 = 48V$.

Answer:

48 V