a set of charged plates 0.00262 m apart have an electric field of 155 n/c between them. what is the…

a set of charged plates 0.00262 m apart have an electric field of 155 n/c between them. what is the potential difference between the plates? (unit = v)

a set of charged plates 0.00262 m apart have an electric field of 155 n/c between them. what is the potential difference between the plates? (unit = v)

Answer

Explanation:

Step1: Identify the formula

The formula for the potential - difference $V$ between two charged plates is $V = Ed$, where $E$ is the electric field and $d$ is the distance between the plates.

Step2: Substitute the given values

We are given that $E = 155\ N/C$ and $d=0.00262\ m$. Substituting these values into the formula, we get $V=(155\ N/C)\times(0.00262\ m)$.

Step3: Calculate the result

$V = 155\times0.00262= 0.4061\ V$.

Answer:

$0.4061$