a set of charged plates has an electric field of 1420 n/c between them. if the potential difference is 75.0…

Explanation:

Step1: Recall the formula

The formula relating electric - field ($E$), potential difference ($V$), and plate separation ($d$) is $E=\frac{V}{d}$.

Step2: Rearrange the formula for $d$

We can rewrite the formula as $d = \frac{V}{E}$.

Step3: Substitute the given values

Given $V = 75.0\ V$ and $E=1420\ N/C$, then $d=\frac{75.0}{1420}$. $d = 0.0528\ m$

Answer:

$0.0528$