which set of numbers gives the correct possible values of l for n = 2?\n0\n0,1\n0,1,2\n0,1,2,3

Explanation:

Step1: Recall the rule for $l$ values

The angular - momentum quantum number $l$ ranges from $0$ to $n - 1$ for a given principal quantum number $n$.

Step2: Calculate possible $l$ values for $n = 2$

When $n=2$, $l$ can take values $l = 0$ and $l = 1$ since $l$ starts from $0$ and goes up to $n - 1=2 - 1 = 1$.

Answer:

0, 1