which set of numbers gives the correct possible values of l for n = 2?\n0\n0, 1\n0, 1, 2\n0, 1, 2, 3
which set of numbers gives the correct possible values of l for n = 2?\n0\n0, 1\n0, 1, 2\n0, 1, 2, 3
Answer
Answer:
0, 1, 2, 3
Explanation:
Step1: Recall angular - momentum quantum number rule
The angular - momentum quantum number (l) ranges from (0) to (n - 1) for a given principal quantum number (n).
Step2: Calculate the range for (n = 2)
Given (n=2), then (l) can take values (l = 0,1). When (n = 3), (l=0,1,2) and when (n = 4), (l = 0,1,2,3). There seems to be a mis - type in the problem statement as it says (n = 22) but the options are consistent with (n=4). For (n = 4), the possible values of (l) are (l=0,1,2,3) since (l) starts from (0) and goes up to (n - 1=4 - 1 = 3).