which set of numbers gives the correct possible values of l for n = 3? 0, 1, 2 0, 1, 2, 3 -2, -1, 0, 1, 2…
which set of numbers gives the correct possible values of l for n = 3? 0, 1, 2 0, 1, 2, 3 -2, -1, 0, 1, 2 -3, -2, -1, 0, 1, 2, 3
Answer
Explanation:
Step1: Recall the rule for angular - momentum quantum number
The angular - momentum quantum number (l) ranges from (0) to (n - 1) for a given principal quantum number (n).
Step2: Calculate the range of (l) for (n = 3)
When (n=3), (l) can take values (l = 0,1,2) since (n-1=3 - 1=2) and (l) starts from (0).
Answer:
0, 1, 2