which set of numbers gives the correct possible values of l for n = 2? 0 0, 1 0, 1, 2 0, 1, 2, 3
which set of numbers gives the correct possible values of l for n = 2? 0 0, 1 0, 1, 2 0, 1, 2, 3
Answer
Explanation:
Step1: Recall angular - momentum quantum number rule
The angular - momentum quantum number $l$ ranges from $0$ to $n - 1$ for a given principal quantum number $n$.
Step2: Calculate possible values of $l$ for $n = 2$
When $n=2$, $l$ can take values $l = 0$ and $l = 1$ since $l$ starts from $0$ and goes up to $n - 1=2 - 1 = 1$.
Answer:
0, 1