situation 4. determine the maximum force p that can be applied without causing movement of the 250 - lb…

situation 4. determine the maximum force p that can be applied without causing movement of the 250 - lb crate that has a center of gravity at g. the coefficient of static friction at the floor is $mu_s = 0.4$.

situation 4. determine the maximum force p that can be applied without causing movement of the 250 - lb crate that has a center of gravity at g. the coefficient of static friction at the floor is $mu_s = 0.4$.

Answer

Explanation:

Step1: Calculate normal force

The weight of the crate $W = 250$ - lb. Since the crate is on a horizontal surface, the normal force $N$ acting on the crate is equal to its weight, so $N=W = 250$ lb.

Step2: Calculate maximum static - friction force

The formula for the maximum static - friction force is $F_s=\mu_sN$. Given $\mu_s = 0.4$ and $N = 250$ lb, we have $F_s=0.4\times250=100$ lb.

Step3: Analyze equilibrium condition for horizontal forces

For the crate not to move, the maximum applied force $P$ is equal to the maximum static - friction force. In the horizontal direction, $\sum F_x = 0$. When the crate is on the verge of moving, $P = F_s$.

Answer:

$P = 100$ lb