when skydiving how far did you fall after 8.2 seconds?\n\n$d = \\frac{1}{2}gt^{2}$

when skydiving how far did you fall after 8.2 seconds?\n\n$d = \\frac{1}{2}gt^{2}$

when skydiving how far did you fall after 8.2 seconds?\n\n$d = \\frac{1}{2}gt^{2}$

Answer

Explanation:

Step1: Identify values

We know that $g = 9.8\ m/s^{2}$ (acceleration due to gravity) and $t = 8.2\ s$.

Step2: Substitute values into formula

$d=\frac{1}{2}\times9.8\times(8.2)^{2}$ First, calculate $(8.2)^{2}=67.24$. Then, $\frac{1}{2}\times9.8 = 4.9$. Finally, $d = 4.9\times67.24=329.476\ m$.

Answer:

$329.476\ m$