a snowmobile with mass 175 kg exerts a force of 85 n in 12 s. the final velocity that it reaches is 30 m/s…

a snowmobile with mass 175 kg exerts a force of 85 n in 12 s. the final velocity that it reaches is 30 m/s. what was the snowmobiles initial velocity?
Answer
Explanation:
Step1: Calculate the acceleration
According to Newton's second law (F = ma), where (F) is the force, (m) is the mass, and (a) is the acceleration. We can find (a=\frac{F}{m}). Substituting (F = 85\space N) and (m=175\space kg), we get (a=\frac{85}{175}\space m/s^{2}\approx0.486\space m/s^{2}).
Step2: Use the kinematic equation (v = u+at)
Here, (v) is the final velocity ((v = 30\space m/s)), (u) is the initial velocity (which we want to find), (a) is the acceleration ((a=\frac{85}{175}\space m/s^{2})), and (t) is the time ((t = 12\space s)). Rearrange the equation for (u): (u=v - at). Substitute the values: (u = 30-\frac{85}{175}\times12). First calculate (\frac{85\times12}{175}=\frac{1020}{175}\approx5.83). Then (u=30 - 5.83=24.17\space m/s)
Answer:
(24.17\space m/s)