sound waves\nbased on the data in the table, which function models the frequency, y, in waves per second, of…

sound waves\nbased on the data in the table, which function models the frequency, y, in waves per second, of sound waves with a wavelength of x meters?\nwavelength, x (m) frequency, y (waves/s)\n0.5 680\n1 340\n1.5 227\n2 170\n2.5 136\n$y = 340^{x}$\n$y=\frac{x}{340}$\n$y = 340x$\n$y=\frac{340}{x}$\ndone

sound waves\nbased on the data in the table, which function models the frequency, y, in waves per second, of sound waves with a wavelength of x meters?\nwavelength, x (m) frequency, y (waves/s)\n0.5 680\n1 340\n1.5 227\n2 170\n2.5 136\n$y = 340^{x}$\n$y=\frac{x}{340}$\n$y = 340x$\n$y=\frac{340}{x}$\ndone

Answer

Explanation:

Step1: Comprobar la relación entre longitud de onda y frecuencia

Multiplicamos los valores de $x$ y $y$ de cada fila de la tabla. Para $x = 0.5$ y $y=680$, $0.5\times680 = 340$. Para $x = 1$ y $y = 340$, $1\times340=340$. Para $x = 1.5$ y $y\approx227$, $1.5\times227 = 340.5\approx340$. Para $x = 2$ y $y = 170$, $2\times170=340$. Para $x = 2.5$ y $y = 136$, $2.5\times136=340$. Vemos que $x\times y=340$, entonces $y=\frac{340}{x}$.

Answer:

$y=\frac{340}{x}$