if the specific gravity of ice is 0.92 g/cm³, what is the density of ice? (1 ml = 1 cm³)
if the specific gravity of ice is 0.92 g/cm³, what is the density of ice? (1 ml = 1 cm³)
Answer
Explanation:
Step1: Recall the definition of specific gravity
Specific gravity is the ratio of the density of a substance to the density of a reference substance (usually water at 4°C with density $\rho_{water}= 1\ g/cm^{3}$). The formula is $SG=\frac{\rho_{substance}}{\rho_{water}}$.
Step2: Rearrange the formula to find the density of the substance
We know $SG = 0.92$ and $\rho_{water}=1\ g/cm^{3}$. Rearranging the formula $SG=\frac{\rho_{substance}}{\rho_{water}}$ gives $\rho_{substance}=SG\times\rho_{water}$.
Step3: Calculate the density of ice
Substitute the values: $\rho_{ice}=0.92\times1\ g/cm^{3}=0.92\ g/cm^{3}$.
Answer:
$0.92\ g/cm^{3}$