the specific heat of aluminum is 0.21 j/g°c. how much heat(q) is released when a 10 g piece of aluminum foil…

Explanation:

Step1: Identify the formula

The formula for heat transfer is $Q = mc\Delta T$, where $m$ is the mass, $c$ is the specific - heat capacity, and $\Delta T$ is the change in temperature.

Step2: Determine the values of variables

$m = 10\ g$, $c=0.21\ J/g^{\circ}C$, $\Delta T=T_{initial}-T_{final}=100^{\circ}C - 50^{\circ}C=50^{\circ}C$.

Step3: Substitute values into the formula

$Q=(10\ g)\times(0.21\ J/g^{\circ}C)\times(50^{\circ}C)$.

Step4: Calculate the result

$Q = 10\times0.21\times50\ J=105\ J$.

Answer:

D. 105 J