6. what is the specific heat capacity of silver metal if 55.00 g of the metal absorbs 47.3j of heat and the…

Explanation:

Step1: Recall the heat - capacity formula

The formula for heat absorbed is $q = mc\Delta T$, where $q$ is the heat absorbed, $m$ is the mass of the substance, $c$ is the specific heat capacity, and $\Delta T$ is the change in temperature. We need to solve for $c$, so we can re - arrange the formula to $c=\frac{q}{m\Delta T}$.

Step2: Identify the given values

We are given that $q = 47.3\ J$, $m = 55.00\ g$, and $\Delta T=15.0^{\circ}C$.

Step3: Substitute the values into the formula

$c=\frac{47.3\ J}{55.00\ g\times15.0^{\circ}C}$ $c=\frac{47.3\ J}{825\ g\cdot^{\circ}C}$ $c = 0.0573\ J/(g\cdot^{\circ}C)$

Answer:

$0.0573\ J/(g\cdot^{\circ}C)$