what is the specific heat of a substance if a mass of 10.0 kg increases in temperature from 10.0°c to 70.0°c…

what is the specific heat of a substance if a mass of 10.0 kg increases in temperature from 10.0°c to 70.0°c when 2,520 j of heat is applied? use $q = mc_pdelta t$.\n0.00420 j/(g°c)\n0.00661 j/(g°c)\n238 j/(g°c)\n252 j/(g°c)

what is the specific heat of a substance if a mass of 10.0 kg increases in temperature from 10.0°c to 70.0°c when 2,520 j of heat is applied? use $q = mc_pdelta t$.\n0.00420 j/(g°c)\n0.00661 j/(g°c)\n238 j/(g°c)\n252 j/(g°c)

Answer

Explanation:

Step1: Calculate temperature change

$\Delta T=T_2 - T_1=70.0^{\circ}C - 10.0^{\circ}C = 60.0^{\circ}C$

Step2: Convert mass to grams

$m = 10.0\ kg=10.0\times1000\ g = 10000\ g$

Step3: Rearrange the heat - capacity formula

$C_p=\frac{q}{m\Delta T}$

Step4: Substitute values

$C_p=\frac{2520\ J}{10000\ g\times60.0^{\circ}C}=\frac{2520}{600000}\ J/(g^{\circ}C)= 0.00420\ J/(g^{\circ}C)$

Answer:

0.00420 J/(g°C)