starting from rest, a professional driver conducted a test drive to cover certain distances in certain…

starting from rest, a professional driver conducted a test drive to cover certain distances in certain amounts of times. the table shows the distances, the times, and the direction of travel.\ntime of travel (s) 0 60 120 180\ndistance from start point (km) 0 2 4 6\ndirection of travel east east east north\nbased on the data, during what portions of the test was the professional driver most likely accelerating? place the corresponding label in each cell of the table below.\nportion of the test from 0 s to 60 s from 60 s to 120 s from 120 s to 180 s\ntype of motion \nevidence \naccelerated non - accelerated\nchange in speed change in direction no change in direction or speed

starting from rest, a professional driver conducted a test drive to cover certain distances in certain amounts of times. the table shows the distances, the times, and the direction of travel.\ntime of travel (s) 0 60 120 180\ndistance from start point (km) 0 2 4 6\ndirection of travel east east east north\nbased on the data, during what portions of the test was the professional driver most likely accelerating? place the corresponding label in each cell of the table below.\nportion of the test from 0 s to 60 s from 60 s to 120 s from 120 s to 180 s\ntype of motion \nevidence \naccelerated non - accelerated\nchange in speed change in direction no change in direction or speed

Answer

Explanation:

Step1: Calculate speed for each interval

For 0 - 60 s: Speed $v_1=\frac{2 - 0}{60-0}=\frac{1}{30}$ km/s. Starting from rest (0 speed initially), speed is increasing, so it's accelerating.

Step2: Analyze 60 - 120 s

For 60 - 120 s: Speed $v_2=\frac{4 - 2}{120 - 60}=\frac{1}{30}$ km/s. Since speed is constant ($v_1 = v_2$) and direction is same (east), it's non - accelerated motion. But there is a change in direction from east to north at 180 s, so evidence for this interval is change in direction.

Step3: Analyze 120 - 180 s

For 120 - 180 s: Speed $v_3=\frac{6 - 4}{180 - 120}=\frac{1}{30}$ km/s. Speed is constant and direction is constant (north) during this interval, so it's non - accelerated with no change in direction or speed.

Answer:

Portion of the Test From 0 s to 60 s From 60 s to 120 s From 120 s to 180 s
Type of Motion accelerated non - accelerated non - accelerated
Evidence change in speed change in direction no change in direction or speed