stefano accidentally dropped his sunglasses off the edge of a canyon as he was looking down. the height…

stefano accidentally dropped his sunglasses off the edge of a canyon as he was looking down. the height, h(t), in meters (as it relates to sea level), of the sunglasses after t seconds, is shown in the table. during its descent, the pair of sunglasses passed by a climber in the canyon 6 seconds after stefano dropped them. to the nearest meter, what is difference in elevation between stefano and the climber? height of sunglasses over time\n| t | h(t) |\n|----|----| \n| 0 | 10 |\n| 1 | 5.1 |\n| 2 | -9.6 |\n| 3 | -34.1 |\n| 4 | -68.4 |\n| 5 | -112.5 |\n| 6 | -166.4 |\n| 7 | -230.1 |\n166 meters\n176 meters\n230 meters\n240 meters

stefano accidentally dropped his sunglasses off the edge of a canyon as he was looking down. the height, h(t), in meters (as it relates to sea level), of the sunglasses after t seconds, is shown in the table. during its descent, the pair of sunglasses passed by a climber in the canyon 6 seconds after stefano dropped them. to the nearest meter, what is difference in elevation between stefano and the climber? height of sunglasses over time\n| t | h(t) |\n|----|----| \n| 0 | 10 |\n| 1 | 5.1 |\n| 2 | -9.6 |\n| 3 | -34.1 |\n| 4 | -68.4 |\n| 5 | -112.5 |\n| 6 | -166.4 |\n| 7 | -230.1 |\n166 meters\n176 meters\n230 meters\n240 meters

Answer

Explanation:

Step1: Determine Stefano's height

When $t = 0$, the height of the sunglasses $h(0)=10$ meters. This is Stefano's height relative to sea - level when he dropped the sunglasses.

Step2: Determine the climber's height

When $t = 6$, the height of the sunglasses $h(6)=- 166.4$ meters. This is the height of the climber relative to sea - level.

Step3: Calculate the height difference

The height difference $\Delta h=h(0)-h(6)$. Substitute the values: $\Delta h = 10-(-166.4)=10 + 166.4 = 176.4\approx176$ meters.

Answer:

176 meters