stelano accidentally dropped his sunglasses off the edge of a canyon as he was looking down. the height, (…

stelano accidentally dropped his sunglasses off the edge of a canyon as he was looking down. the height, ( h(t) ), in meters (as it relates to sea - level), of the sunglasses after ( t ) seconds, is shown in the table.\n\nduring its descent, the pair of sunglasses passed by a climber in the canyon 6 seconds after stelano dropped them. to the nearest meter, what is the difference in elevation between stelano and the climber?\n\nheight of sunglasses over time\n| ( t ) | ( h(t) ) |\n|----|----| \n| 0 | 10 |\n| 1 | 5.1 |\n| 2 | -9.6 |\n| 3 | -34.1 |\n| 4 | -63.4 |\n| 5 | -112.5 |\n| 6 | -168.4 |\n| 7 | -230.1 |\n\n240 meters\n170 meters\n166 meters\n230 meters
Answer
Explanation:
Step1: Identify initial height
The initial height of the sunglasses when (t = 0) is (h(0)=10) meters. This represents Stefano's elevation relative to sea - level (since it's the height of the sunglasses when he drops them).
Step2: Identify climber's height
When (t = 6) seconds, the height of the sunglasses is (h(6)=- 166.4) meters. This is the climber's elevation relative to sea - level.
Step3: Calculate elevation difference
The difference in elevation (\Delta h) is given by (h(0)-h(6)). So, (\Delta h=10-(-166.4)=10 + 166.4 = 176.4\approx176) meters.
Answer:
166 meters