which step will decrease the pressure of a gas inside a closed cubical container?\no increasing the number…

Explanation:

Step1: Recall ideal gas law

The ideal gas law is $PV = nRT$, where $P$ is pressure, $V$ is volume, $n$ is the number of moles, $R$ is the ideal - gas constant, and $T$ is temperature.

Step2: Analyze each option

• Option 1: Increasing $n$ (number of moles) while $V$ and $T$ are constant. From $P=\frac{nRT}{V}$, an increase in $n$ will increase $P$.
• Option 2: Decreasing $V$ (volume) while $n$ and $T$ are constant. From $P=\frac{nRT}{V}$, a decrease in $V$ will increase $P$.
• Option 3: Increasing the speed of gas particles means increasing the temperature (since temperature is related to the average kinetic energy of gas particles). From $P=\frac{nRT}{V}$, an increase in $T$ will increase $P$.
• Option 4: Decreasing $T$ (temperature) while $n$ and $V$ are constant. From $P=\frac{nRT}{V}$, a decrease in $T$ will decrease $P$.

Answer:

decreasing the temperature inside the container