which step will decrease the pressure of a gas inside a closed cubical container?\n increasing the number of…

Answer:

decreasing the temperature inside the container

Explanation:

Step1: Recall ideal - gas law

$PV = nRT$ (where $P$ is pressure, $V$ is volume, $n$ is number of moles, $R$ is gas constant, $T$ is temperature).

Step2: Analyze each option

• Increasing $n$ (number of moles) while $V$ and $T$ are constant: From $P=\frac{nRT}{V}$, $P$ increases.
• Decreasing $V$ while $n$ and $T$ are constant: From $P=\frac{nRT}{V}$, $P$ increases.
• Increasing the speed of gas particles means increasing $T$ (since temperature is related to average kinetic energy of particles). From $P=\frac{nRT}{V}$, $P$ increases.
• Decreasing $T$ while $n$ and $V$ are constant: From $P=\frac{nRT}{V}$, $P$ decreases.