which step will decrease the pressure of a gas inside a closed cubical container? increasing the number of…

Explanation:

Step1: Recall ideal gas law

The ideal - gas law is $PV = nRT$, where $P$ is pressure, $V$ is volume, $n$ is the number of moles, $R$ is the ideal gas constant, and $T$ is temperature.

Step2: Analyze each option

• Increasing the number of moles of gas ($n$): From $PV=nRT$, if $V$ and $T$ are constant, an increase in $n$ will cause an increase in $P$ since $P=\frac{nRT}{V}$.
• Decreasing the volume of the container ($V$): If $n$ and $T$ are constant, from $P=\frac{nRT}{V}$, a decrease in $V$ will cause an increase in $P$.
• Increasing the speed of the gas particles: The speed of gas particles is related to temperature ($v\propto\sqrt{T}$). Increasing the speed means increasing the temperature. From $P=\frac{nRT}{V}$, if $n$ and $V$ are constant, an increase in $T$ will cause an increase in $P$.
• Decreasing the temperature inside the container ($T$): If $n$ and $V$ are constant, from $P=\frac{nRT}{V}$, a decrease in $T$ will cause a decrease in $P$.

Answer:

Decreasing the temperature inside the container